package com.sea.leetcode;
import java.util.Date;
/**
* Created by Kings on 2016/11/18.
* Description:
* <p>
* You are given two linked lists representing two non-negative numbers.
* The digits are stored in reverse order and each of their nodes contain a single digit.
* Add the two numbers and return it as a linked list.
* Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
* Output: 7 -> 0 -> 8
* <p>
* Custom Testcase:
* [2,4,3]
* [5,6,4]
*
* 这种算法其实可以用来计算大整数
*/
public class AddTwoNumbers {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
ListNode sumNode = null;
ListNode sumHeadNode = null;
int tempvalue = 0;
if (l1 == null) {
sumHeadNode = l2;
} else if (l2 == null) {
sumHeadNode = l1;
} else {
while (l1 != null || l2 != null || tempvalue > 0) {
if (l1 == null) l1 = new ListNode(0);
if (l2 == null) l2 = new ListNode(0);
int nodeSum = l1.val + l2.val + tempvalue;
int digitNode = nodeSum % 10;
if (sumNode == null) {
sumNode = new ListNode(digitNode);
sumHeadNode = sumNode;
} else {
sumNode.next = new ListNode(digitNode);
sumNode = sumNode.next;
}
tempvalue = nodeSum / 10;
l1 = l1.next;
l2 = l2.next;
}
}
return sumHeadNode;
}
public static void main(String[] args) {
ListNode l1 = new ListNode(3);
l1.next = new ListNode(7);
// l1.next.next = new ListNode(3);
ListNode l2 = new ListNode(9);
l2.next = new ListNode(2);
// l2.next.next = new ListNode(4);
//
AddTwoNumbers atn = new AddTwoNumbers();
System.out.println(new Date().getTime());
ListNode resultListNode = atn.addTwoNumbers(l1, l2);
System.out.println(new Date().getTime());
while (resultListNode != null) {
System.out.println(resultListNode.val);
resultListNode = resultListNode.next;
}
}
}
class ListNode {
int val;
ListNode next;
public ListNode(int val) {
this.val = val;
}
}